g) \( \quad-4 \leq \frac{2}{2} \leq 8 \) Solve the pairs of simultaneous equatio a) \( 3 x+5 y=5 ; 3 x+y=9 \)

Solve the equation \( 3x+5y=5;3x+y=9 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}3x+5y=5\\3x+y=9\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}3x+5y=5\\y=9-3x\end{array}\right.\) - step2: Substitute the value of \(y:\) \(3x+5\left(9-3x\right)=5\) - step3: Simplify: \(-12x+45=5\) - step4: Move the constant to the right side: \(-12x=5-45\) - step5: Subtract the numbers: \(-12x=-40\) - step6: Change the signs: \(12x=40\) - step7: Divide both sides: \(\frac{12x}{12}=\frac{40}{12}\) - step8: Divide the numbers: \(x=\frac{10}{3}\) - step9: Substitute the value of \(x:\) \(y=9-3\times \frac{10}{3}\) - step10: Calculate: \(y=-1\) - step11: Calculate: \(\left\{ \begin{array}{l}x=\frac{10}{3}\\y=-1\end{array}\right.\) - step12: Check the solution: \(\left\{ \begin{array}{l}x=\frac{10}{3}\\y=-1\end{array}\right.\) - step13: Rewrite: \(\left(x,y\right) = \left(\frac{10}{3},-1\right)\) The solution to the system of equations \(3x+5y=5\) and \(3x+y=9\) is \(x = \frac{10}{3}\) and \(y = -1\).