Solve the following system of equations. $$ \begin{array}{l}9 x+6 y=-3 \ 5 x+6 y=9\end{array} $$ $$ y=\square $$

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1. Write the system of equations:
   $$
   \begin{aligned}
   9x + 6y &= -3, \
   5x + 6y &= 9.
   \end{aligned}
   $$

2. Subtract the second equation from the first to eliminate $$ y $$:
   $$
   \begin{aligned}
   (9x + 6y) - (5x + 6y) &= -3 - 9, \
   9x - 5x &= -12, \
   4x &= -12.
   \end{aligned}
   $$

3. Solve for $$ x $$:
   $$
   x = \frac{-12}{4} = -3.
   $$

4. Substitute $$ x = -3 $$ into one of the original equations (using $$ 5x + 6y = 9 $$):
   $$
   5(-3) + 6y = 9 \quad \Longrightarrow \quad -15 + 6y = 9.
   $$

5. Solve for $$ y $$:
   $$
   \begin{aligned}
   6y &= 9 + 15, \
   6y &= 24, \
   y &= \frac{24}{6} = 4.
   \end{aligned}
   $$

$$ y=4 $$
$$ y = 4 $$

Solve the following system of equations.

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