a) \( 2-3 \cdot(x-5)=2 \cdot(3 x-5) \)

To solve the equation \( 2-3 \cdot(x-5)=2 \cdot(3 x-5) \), first start by distributing both sides. On the left side, you have \( 2 - 3x + 15 \), which simplifies to \( 17 - 3x \). On the right side, distribute to get \( 6x - 10 \). Now the equation looks like \( 17 - 3x = 6x - 10 \). Next, let's bring the \( x \)-terms to one side and the constants to the other side. Add \( 3x \) to both sides to get \( 17 = 9x - 10 \). Now add 10 to both sides: \( 27 = 9x \). Finally, divide both sides by 9, giving you \( x = 3 \). So, the solution to the equation is \( x = 3 \).