Solve for \( b \). Express your answer as a proper or improper fraction in simplest terms. \[ -\frac{1}{6}=\frac{1}{2} b+\frac{5}{6} \]

To solve for \( b \), we start by isolating it in the equation: \[ -\frac{1}{6} = \frac{1}{2}b + \frac{5}{6} \] First, subtract \( \frac{5}{6} \) from both sides: \[ -\frac{1}{6} - \frac{5}{6} = \frac{1}{2}b \] Combine the fractions on the left side: \[ -\frac{6}{6} = \frac{1}{2}b \] This simplifies to: \[ -1 = \frac{1}{2}b \] Next, to eliminate the fraction, multiply both sides by 2: \[ -2 = b \] Thus, the solution is: \[ b = -2 \]