(4) \( \left\{\begin{array}{l}3 x+5 y=7 \\ 2 x-y=-4\end{array}\right. \)

Solve the system of equations \( 3x+5y=7;2x-y=-4 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}3x+5y=7\\2x-y=-4\end{array}\right.\) - step1: Solve the equation: \(\left\{ \begin{array}{l}3x+5y=7\\y=4+2x\end{array}\right.\) - step2: Substitute the value of \(y:\) \(3x+5\left(4+2x\right)=7\) - step3: Simplify: \(13x+20=7\) - step4: Move the constant to the right side: \(13x=7-20\) - step5: Subtract the numbers: \(13x=-13\) - step6: Divide both sides: \(\frac{13x}{13}=\frac{-13}{13}\) - step7: Divide the numbers: \(x=-1\) - step8: Substitute the value of \(x:\) \(y=4+2\left(-1\right)\) - step9: Substitute back: \(y=4-2\) - step10: Calculate: \(y=2\) - step11: Calculate: \(\left\{ \begin{array}{l}x=-1\\y=2\end{array}\right.\) - step12: Check the solution: \(\left\{ \begin{array}{l}x=-1\\y=2\end{array}\right.\) - step13: Rewrite: \(\left(x,y\right) = \left(-1,2\right)\) La solución de las ecuaciones dadas es \( x = -1 \) y \( y = 2 \).