Euler's formula, \( V-E+F=2 \) relates the number of vertices \( V \), the number of edges \( E \), and the number of faces \( F \) of a polyhedron. How many faces does a polyhedron with 4 vertices and 6 edges have? 6 4 7

To find the number of faces \( F \) using Euler's formula \( V - E + F = 2 \), we can substitute the known values: \( V = 4 \) and \( E = 6 \). Plugging these into the formula, we get: \[ 4 - 6 + F = 2 \] Simplifying this gives: \[ -2 + F = 2 \] Adding 2 to both sides results in: \[ F = 4 \] So, the polyhedron has 4 faces. Now, your answer is \( 4 \). Good job!