6. Jazara, Riya and Divya share 10 biscuits so that Jazara has 2, Riya has 6 and Divya has the remainder. (a) Determine in the simplest form the ratio used to share the biscuit among the girls in the order to Jazara to Riya to Divya. (b) If the girls received 25 biscuits, using the ratio from part (a) how many biscuits would Divya receive? ( 4 marks)

To determine the simplest form of the ratio in which the biscuits are shared, we have Jazara's 2 biscuits, Riya's 6 biscuits, and Divya's remainder which is 10 - (2 + 6) = 2 biscuits. The ratio of Jazara to Riya to Divya can thus be expressed as 2:6:2. Simplifying this gives a final ratio of 1:3:1. For part (b), using the ratio of 1:3:1, we can add the parts together, which gives us 1 + 3 + 1 = 5 parts in total. For 25 biscuits shared, each part is worth 25/5 = 5 biscuits. Therefore, Divya, who has 1 part, would receive 1 × 5 = 5 biscuits.