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Divide. Assume that no denominator equals zero. \( \begin{array}{l}\frac{20 y^{14}}{4 y^{2}} \\ \begin{array}{ll}\text { a. } 5 y^{28} & \text { c. } 5 y^{12} \\ \text { b. } 4 y^{-12} & \text { d. } 5 y^{16}\end{array}\end{array} \)

Ask by Mitchell Ray. in the United States
Mar 13,2025

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Answer

The answer is \(5y^{12}\).

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The Deep Dive

To simplify \(\frac{20 y^{14}}{4 y^{2}}\), start by simplifying the coefficients first: \( \frac{20}{4} = 5\). Next, apply the properties of exponents: \( \frac{y^{14}}{y^{2}} = y^{14-2} = y^{12}\). Therefore, the result is \(5 y^{12}\). So the correct answer is: **5 y^{12}, option c.** For a little more fun: mathematicians have been refining division techniques since ancient civilizations like the Egyptians, who had their own unique ways to tackle fractions. So each time you simplify like this, you're part of a long history of problem solvers! And remember, common mistakes often happen when students forget to subtract the exponents correctly. Always double-check your calculations; it’s like getting a second scoop of ice cream—totally worth it!

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