2) \( \left(1+\frac{1}{2}\right)^{2}-\sqrt{2+\frac{1}{11}}-\frac{3}{5}= \)
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To solve the expression \( \left(1+\frac{1}{2}\right)^{2}-\sqrt{2+\frac{1}{11}}-\frac{3}{5} \): First, calculate \( \left(1+\frac{1}{2}\right)^{2} = \left(\frac{3}{2}\right)^{2} = \frac{9}{4} \). Next, simplify \( \sqrt{2+\frac{1}{11}} \): Convert \( 2 \) into a fraction: \( 2 = \frac{22}{11} \), so \( 2 + \frac{1}{11} = \frac{22}{11} + \frac{1}{11} = \frac{23}{11} \). Now, \( \sqrt{2+\frac{1}{11}} = \sqrt{\frac{23}{11}} = \frac{\sqrt{23}}{\sqrt{11}} \). Now, turn to \( \frac{3}{5} \). Putting it all together: We need to calculate \( \frac{9}{4} - \frac{\sqrt{23}}{\sqrt{11}} - \frac{3}{5} \). To subtract these fractions, we first find a common denominator, which can be \( 20 \) since it's the least common multiple of \( 4 \) and \( 5 \). Rewriting the fractions: - \( \frac{9}{4} = \frac{45}{20} \) - \( \frac{3}{5} = \frac{12}{20} \) So we now have: \( \frac{45}{20} - \frac{12}{20} - \frac{\sqrt{23}}{\sqrt{11}} \) = \( \frac{33}{20} - \frac{\sqrt{23}}{\sqrt{11}} \). The final answer is \( \frac{33}{20} - \frac{\sqrt{23}}{\sqrt{11}} \). If desired, this could be further simplified but still remains the exact value in this form.