Solve for $$ p $$ $$ 41 p^{2}+46 p=0 $$

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UpStudy AI · Accepted Answer

1. Start with the equation:
   
   $$
   41p^2 + 46p = 0
   $$

2. Factor out the common factor $$ p $$:

$$
   p(41p + 46) = 0
   $$

3. Set each factor equal to zero and solve:

- For the first factor:
     
     $$
     p = 0
     $$
   
   - For the second factor:
     
     $$
     41p + 46 = 0 \quad \Rightarrow \quad 41p = -46 \quad \Rightarrow \quad p = -\frac{46}{41}
     $$

4. The solutions for $$ p $$ are:

$$
   p = 0 \quad \text{or} \quad p = -\frac{46}{41}
   $$
The solutions for $$ p $$ are $$ p = 0 $$ and $$ p = -\frac{46}{41} $$.

Solve for \( p \) \[ 41 p^{2}+46 p=0 \]

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