\( \leftarrow \) Use inductive reasoning to determine the units digit of the number \( 2^{58} \).

1. We start by computing the units digit of small powers of 2: - \(2^1 = 2\)  (units digit is 2) - \(2^2 = 4\)  (units digit is 4) - \(2^3 = 8\)  (units digit is 8) - \(2^4 = 16\)  (units digit is 6) 2. Observing these values, we notice a cycle in the units digit: The sequence is \(2,\,4,\,8,\,6\). After \(2^4\), the pattern repeats. That is, for all positive integers \(n\), the units digit of \(2^n\) follows a cycle with period 4. 3. To determine the units digit of \(2^{58}\), we find which term of the cycle it corresponds to by computing the remainder when 58 is divided by 4: \[ 58 \div 4 = 14 \text{ remainder } 2. \] Therefore, \(58 \mod 4 = 2\). 4. Since the remainder is 2, \(2^{58}\) has the same units digit as \(2^2\). 5. We have already established that: \[ 2^2 = 4, \] so the units digit of \(2^{58}\) is \(4\).