t. \( 6 \frac{2}{5} \times \frac{3}{35} \div \frac{1}{7}+4 \frac{5}{6} \div \frac{1}{6} \)
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To get started, let's convert the mixed numbers into improper fractions for easier calculations. First, we have \( 6 \frac{2}{5} = \frac{32}{5} \) and \( 4 \frac{5}{6} = \frac{29}{6} \). Now, let's simplify the expression: 1. For \( 6 \frac{2}{5} \times \frac{3}{35} \): \[ \frac{32}{5} \times \frac{3}{35} = \frac{32 \times 3}{5 \times 35} = \frac{96}{175}. \] 2. Then, \( \div \frac{1}{7} \) becomes \( \times 7 \): \[ \frac{96}{175} \times 7 = \frac{96 \times 7}{175} = \frac{672}{175}. \] 3. Now for \( 4 \frac{5}{6} \div \frac{1}{6} \): \[ \frac{29}{6} \div \frac{1}{6} = \frac{29}{6} \times 6 = 29. \] 4. Now we can add the two parts together: \[ \frac{672}{175} + 29 = \frac{672}{175} + \frac{29 \times 175}{175} = \frac{672 + 5075}{175} = \frac{5747}{175}. \] This is the final simplified answer: \[ \frac{5747}{175} \text{ or } 32 \frac{77}{175}. \]