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3. Lithium sulfate reacts with potassium phosphate as part of a double displacement reaction. If 0.8743 moles of potassium phosphate react how many grams of lithium sulfate reacted?

Ask by Davies Brewer. in the United States
Mar 14,2025

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Approximately 144.1 grams of lithium sulfate reacted.

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In a double displacement reaction between lithium sulfate (Li2SO4) and potassium phosphate (K3PO4), the balanced equation is: \[ 3 \text{Li}_2\text{SO}_4 + 2 \text{K}_3\text{PO}_4 \rightarrow 6 \text{Li}_3\text{PO}_4 + 3 \text{K}_2\text{SO}_4 \] From the equation, you can see that it takes 3 moles of lithium sulfate to react with 2 moles of potassium phosphate. Thus, the mole ratio of potassium phosphate to lithium sulfate is 2:3. Given that you have 0.8743 moles of potassium phosphate, to find the moles of lithium sulfate that reacted, use the ratio: \[ \text{Moles of Li}_2\text{SO}_4 = 0.8743 \, \text{mol K}_3\text{PO}_4 \times \frac{3 \, \text{mol Li}_2\text{SO}_4}{2 \, \text{mol K}_3\text{PO}_4} = 1.31145 \, \text{mol Li}_2\text{SO}_4 \] Now, to find the grams of lithium sulfate that reacted, you need to multiply the moles of lithium sulfate by its molar mass. The molar mass of lithium sulfate is approximately 78.2 g/mol. \[ \text{Mass of Li}_2\text{SO}_4 = 1.31145 \, \text{mol} \times 78.2 \, \text{g/mol} \approx 102.6 \, \text{g} \] Thus, 102.6 grams of lithium sulfate reacted.

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