3) \( \begin{array}{l}y=3 x-19 \\ -x-2 y=-18\end{array} \)

Solve the system of equations \( y=3x-19;-x-2y=-18 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}y=3x-19\\-x-2y=-18\end{array}\right.\) - step1: Substitute the value of \(y:\) \(-x-2\left(3x-19\right)=-18\) - step2: Simplify: \(-7x+38=-18\) - step3: Move the constant to the right side: \(-7x=-18-38\) - step4: Subtract the numbers: \(-7x=-56\) - step5: Change the signs: \(7x=56\) - step6: Divide both sides: \(\frac{7x}{7}=\frac{56}{7}\) - step7: Divide the numbers: \(x=8\) - step8: Substitute the value of \(x:\) \(y=3\times 8-19\) - step9: Calculate: \(y=5\) - step10: Calculate: \(\left\{ \begin{array}{l}x=8\\y=5\end{array}\right.\) - step11: Check the solution: \(\left\{ \begin{array}{l}x=8\\y=5\end{array}\right.\) - step12: Rewrite: \(\left(x,y\right) = \left(8,5\right)\) The solution to the system of equations is \( (x,y) = (8,5) \).