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How many solutions does this equation have? \[ -12+15 b=-3(-5 b+4) \]

Ask by Bond Christensen. in Ecuador
Jan 14,2025

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Answer

There are infinitely many solutions; any real number \( b \) satisfies the equation.

Solution

Let's analyze the given equation: \[ -12 + 15b = -3(-5b + 4) \] **Step 1: Simplify the Right Side** First, distribute the \(-3\) on the right side: \[ -3(-5b + 4) = 15b - 12 \] **Step 2: Rewrite the Equation** Now, the equation becomes: \[ -12 + 15b = 15b - 12 \] **Step 3: Compare Both Sides** Subtract \(15b\) from both sides: \[ -12 = -12 \] This simplifies to a true statement that holds for all real numbers \(b\). **Conclusion:** Since the equation simplifies to a true statement irrespective of the value of \(b\), there are **infinitely many solutions**. In other words, **any real number** \(b\) satisfies the equation. **Answer:** There are infinitely many real solutions; every real number b satisfies the equation.

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To find the number of solutions for the equation \( -12 + 15b = -3(-5b + 4) \), we first simplify both sides. Starting with the right side: \[ -3(-5b + 4) = 15b - 12 \] Now our equation becomes: \[ -12 + 15b = 15b - 12 \] Next, we subtract \( 15b \) from both sides: \[ -12 = -12 \] This equation is always true, which means the original equation has infinitely many solutions. The variable \( b \) can take any value, resulting in a slew of possible solutions. It's like having an entire line of solutions rather than just isolated points! Thus, the equation simplifies to a true statement, indicating that it's valid for any \( b \).

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