Question
upstudy study bank question image url

Score:0/2 Penaltro 05 alf Question Watch Video If \( f(x)=x^{3}+3 x^{2}-33 x-35 \), which of the following is not a factor of \( f(x) \) ? Answer \( (x+7) \) \( (x-5) \) \( (x+1) \) \( (x+5) \)

Ask by Bush Hammond. in the United States
Feb 24,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

\( (x + 5) \) is not a factor of \( f(x) \).

Solution

We are given the function f(x) = x³ + 3x² - 33x - 35, and we need to determine which of the provided factors is not a factor of f(x). To check if a linear polynomial (x - a) (or equivalently (x + b), where b = -a) is a factor of f(x), we can use the Factor Theorem. The theorem states that (x - a) is a factor if and only if f(a) = 0. Let's test each candidate: 1. For (x + 7), set x = -7: f(-7) = (-7)³ + 3(-7)² - 33(-7) - 35 = -343 + 3(49) + 231 - 35 = -343 + 147 + 231 - 35 = 0. So, (x + 7) is a factor. 2. For (x - 5), set x = 5: f(5) = (5)³ + 3(5)² - 33(5) - 35 = 125 + 75 - 165 - 35 = 0. So, (x - 5) is a factor. 3. For (x + 1), set x = -1: f(-1) = (-1)³ + 3(-1)² - 33(-1) - 35 = -1 + 3 + 33 - 35 = 0. So, (x + 1) is a factor. 4. For (x + 5), set x = -5: f(-5) = (-5)³ + 3(-5)² - 33(-5) - 35 = -125 + 75 + 165 - 35 = 80 (not 0). So, (x + 5) is not a factor. Therefore, the factor that is not a factor of f(x) is (x + 5).

Answered by UpStudy AI and reviewed by a Professional Tutor

error msg
Explain
Simplify this solution

Extra Insights

To find which of the given options is not a factor of \( f(x) = x^{3} + 3x^{2} - 33x - 35 \), we can use the Factor Theorem. This theorem states that if \( f(c) = 0 \) for some value \( c \), then \( (x - c) \) is a factor of \( f(x) \). We can evaluate \( f(x) \) for each option: 1. For \( (x+7) \), plug in \( x = -7 \): \( f(-7) = (-7)^{3} + 3(-7)^{2} - 33(-7) - 35 = -343 + 147 + 231 - 35 = 0 \). So, \( (x + 7) \) is a factor. 2. For \( (x-5) \), plug in \( x = 5 \): \( f(5) = (5)^{3} + 3(5)^{2} - 33(5) - 35 = 125 + 75 - 165 - 35 = 0 \). So, \( (x - 5) \) is a factor. 3. For \( (x+1) \), plug in \( x = -1 \): \( f(-1) = (-1)^{3} + 3(-1)^{2} - 33(-1) - 35 = -1 + 3 + 33 - 35 = 0 \). So, \( (x + 1) \) is a factor. 4. For \( (x+5) \), plug in \( x = -5 \): \( f(-5) = (-5)^{3} + 3(-5)^{2} - 33(-5) - 35 = -125 + 75 + 165 - 35 = 80 \). Since \( f(-5) \neq 0 \), \( (x + 5) \) is not a factor. Thus, the option that is not a factor of \( f(x) \) is \( (x + 5) \).

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy