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Prove that: \( |a| \geq 9 \)

Ask by Medina Greene. in South Africa
Mar 12,2025

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To prove that \( |a| \geq 9 \), consider two cases: 1. If \( a \geq 0 \), then \( |a| = a \geq 9 \). 2. If \( a < 0 \), then \( |a| = -a \geq 9 \), which means \( a \leq -9 \). Therefore, \( |a| \geq 9 \) when \( a \geq 9 \) or \( a \leq -9 \).

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Beyond the Answer

To prove that \( |a| \geq 9 \), we can start by analyzing the definition of absolute value. The absolute value \( |a| \) represents the distance of \( a \) from zero on the number line. Therefore, if \( |a| \geq 9 \), it means that \( a \) is either greater than or equal to 9 or less than or equal to -9. We can express this with the inequalities: 1. \( a \geq 9 \) or 2. \( a \leq -9 \) Thus, unless \( a \) falls within the range \(-9 < a < 9\), which contradicts the absolute value condition, we can confidently conclude that \( |a| \) must indeed be greater than or equal to 9. One way to demonstrate this is by considering specific cases of values for \( a \) that satisfy the conditions of the absolute value, confirming that they will produce values meeting or exceeding 9.

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