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3. Expresa en forma de intervalo los entornos \( \begin{array}{ll}\text { a. } E_{4}(-2) & \text { b. } E_{2}(5) \\ \text { c. } E_{3}(10) & \text { d. } E_{5}(-3) \\ \text { e. } E_{1}(-7) & \text { f. } E_{6}(1)\end{array} \)

Ask by Wheeler Welch. in Colombia
Mar 09,2025

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Answer

a. \( E_4(-2) = (-6, 2) \) b. \( E_2(5) = (3, 7) \) c. \( E_3(10) = (7, 13) \) d. \( E_5(-3) = (-8, 2) \) e. \( E_1(-7) = (-8, -6) \) f. \( E_6(1) = (-5, 7) \)

Solution

Consideramos que para un entorno \( E_r(x_0) \) el intervalo que lo representa es \[ (x_0 - r,\; x_0 + r) \] procediendo de la siguiente manera: 1. Para \( E_4(-2) \): - Calculamos: \(-2 - 4 = -6\) y \(-2 + 4 = 2\). - Así, \( E_4(-2) = (-6, 2) \). 2. Para \( E_2(5) \): - Calculamos: \(5 - 2 = 3\) y \(5 + 2 = 7\). - Entonces, \( E_2(5) = (3, 7) \). 3. Para \( E_3(10) \): - Calculamos: \(10 - 3 = 7\) y \(10 + 3 = 13\). - De modo que, \( E_3(10) = (7, 13) \). 4. Para \( E_5(-3) \): - Calculamos: \(-3 - 5 = -8\) y \(-3 + 5 = 2\). - Por lo tanto, \( E_5(-3) = (-8, 2) \). 5. Para \( E_1(-7) \): - Calculamos: \(-7 - 1 = -8\) y \(-7 + 1 = -6\). - Así, \( E_1(-7) = (-8, -6) \). 6. Para \( E_6(1) \): - Calculamos: \(1 - 6 = -5\) y \(1 + 6 = 7\). - Concluimos que, \( E_6(1) = (-5, 7) \).

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¡Claro! Vamos a convertir esos entornos en intervalos, utilizando la notación que aparece generalmente en matemáticas. a. \( E_{4}(-2) = (-6, 2) \) b. \( E_{2}(5) = (3, 7) \) c. \( E_{3}(10) = (7, 13) \) d. \( E_{5}(-3) = (-8, 2) \) e. \( E_{1}(-7) = (-8, -6) \) f. \( E_{6}(1) = (-5, 7) \) Siéntete libre de preguntar cualquier otra cosa. ¡Matemáticas son pura diversión!

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