Answer
a) \( \frac{x}{4} + \frac{3}{7} = \frac{7x + 12}{28} \)
b) \( \frac{2x}{4+x} + \frac{x}{3} = \frac{10x + x^{2}}{12 + 3x} \)
c) \( \frac{a+1}{b} \times \frac{b^{2}}{a^{2}-1} = \frac{b}{a-1} \)
Solution
Calculate or simplify the expression \( (x/4)+(3/7) \).
Simplify the expression by following steps:
- step0: Solution:
\(\frac{x}{4}+\frac{3}{7}\)
- step1: Reduce fractions to a common denominator:
\(\frac{x\times 7}{4\times 7}+\frac{3\times 4}{7\times 4}\)
- step2: Multiply the numbers:
\(\frac{x\times 7}{28}+\frac{3\times 4}{7\times 4}\)
- step3: Multiply the numbers:
\(\frac{x\times 7}{28}+\frac{3\times 4}{28}\)
- step4: Transform the expression:
\(\frac{x\times 7+3\times 4}{28}\)
- step5: Reorder the terms:
\(\frac{7x+3\times 4}{28}\)
- step6: Multiply the numbers:
\(\frac{7x+12}{28}\)
Calculate or simplify the expression \( (2*x/(4+x))+(x/3) \).
Simplify the expression by following steps:
- step0: Solution:
\(\left(\frac{2x}{\left(4+x\right)}\right)+\frac{x}{3}\)
- step1: Remove the parentheses:
\(\left(\frac{2x}{4+x}\right)+\frac{x}{3}\)
- step2: Remove the parentheses:
\(\frac{2x}{4+x}+\frac{x}{3}\)
- step3: Reduce fractions to a common denominator:
\(\frac{2x\times 3}{\left(4+x\right)\times 3}+\frac{x\left(4+x\right)}{3\left(4+x\right)}\)
- step4: Reorder the terms:
\(\frac{2x\times 3}{3\left(4+x\right)}+\frac{x\left(4+x\right)}{3\left(4+x\right)}\)
- step5: Transform the expression:
\(\frac{2x\times 3+x\left(4+x\right)}{3\left(4+x\right)}\)
- step6: Multiply the terms:
\(\frac{6x+x\left(4+x\right)}{3\left(4+x\right)}\)
- step7: Multiply the terms:
\(\frac{6x+4x+x^{2}}{3\left(4+x\right)}\)
- step8: Add the terms:
\(\frac{10x+x^{2}}{3\left(4+x\right)}\)
- step9: Simplify:
\(\frac{10x+x^{2}}{12+3x}\)
Calculate or simplify the expression \( ((a+1)/b)*((b^2)/(a^2-1)) \).
Simplify the expression by following steps:
- step0: Solution:
\(\left(\frac{\left(a+1\right)}{b}\right)\left(\frac{b^{2}}{\left(a^{2}-1\right)}\right)\)
- step1: Remove the parentheses:
\(\left(\frac{a+1}{b}\right)\left(\frac{b^{2}}{a^{2}-1}\right)\)
- step2: Remove the parentheses:
\(\frac{a+1}{b}\times \left(\frac{b^{2}}{a^{2}-1}\right)\)
- step3: Remove the parentheses:
\(\frac{a+1}{b}\times \frac{b^{2}}{a^{2}-1}\)
- step4: Rewrite the expression:
\(\frac{a+1}{b}\times \frac{b^{2}}{\left(a+1\right)\left(a-1\right)}\)
- step5: Reduce the fraction:
\(1\times \frac{b}{a-1}\)
- step6: Multiply the terms:
\(\frac{b}{a-1}\)
The simplified expressions are:
a) \( \frac{x}{4}+\frac{3}{7} = \frac{7x+12}{28} \)
b) \( \frac{2x}{4+x}+\frac{x}{3} = \frac{10x+x^{2}}{12+3x} \)
c) \( \frac{a+1}{b} \times \frac{b^{2}}{a^{2}-1} = \frac{b}{a-1} \)
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