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\( \frac { d } { d x } ( 3 x ^ { 2 } + 4 x y = 2 ) \)

Ask by Ortega Page. in the Philippines
Feb 28,2025

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Answer

The derivative \( \frac{dy}{dx} \) is \( -\frac{3x + 2y}{2x} \).

Solution

We start with the equation:   3x² + 4xy = 2 Differentiate both sides with respect to x. Remember that when differentiating 4xy, we must use the product rule since y is a function of x. Step 1. Differentiate term-by-term: • The derivative of 3x² is 6x. • For 4xy, apply the product rule:   d/dx (xy) = x · (dy/dx) + y · 1   Thus, the derivative of 4xy is 4(x·(dy/dx) + y). • The derivative of the constant 2 is 0. So we have:   6x + 4(x·(dy/dx) + y) = 0 Step 2. Simplify and solve for dy/dx: Expand the expression:   6x + 4x·(dy/dx) + 4y = 0 Isolate the term containing dy/dx:   4x·(dy/dx) = –6x – 4y Divide both sides by 4x (assuming x ≠ 0):   dy/dx = (–6x – 4y) / (4x) We can simplify the fraction by dividing the numerator and denominator by 2:   dy/dx = (–3x – 2y) / (2x) Thus, the derivative dy/dx is:   dy/dx = –(3x + 2y) / (2x)

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Bonus Knowledge

To differentiate the equation \( 3x^2 + 4xy = 2 \) with respect to \( x \), you need to apply implicit differentiation as \( y \) is also a function of \( x \). The derivative will be: \[ \frac{d}{dx}(3x^2) + \frac{d}{dx}(4xy) = \frac{d}{dx}(2) \] Using the product rule for the term \( 4xy \): \[ 6x + 4 \left( x \frac{dy}{dx} + y \right) = 0 \] Now, isolate \( \frac{dy}{dx} \): \[ 6x + 4x \frac{dy}{dx} + 4y = 0 \implies 4x \frac{dy}{dx} = -6x - 4y \implies \frac{dy}{dx} = \frac{-6x - 4y}{4x} = -\frac{3}{2} - \frac{y}{x} \] Let’s keep going! Remember that getting comfortable with implicit differentiation is all about practice! Once you get the hang of it, you’ll be breezing through equations while impressing your friends with your math wizardry! Did you know that implicit differentiation was first introduced by mathematicians like René Descartes and Gottfried Wilhelm Leibniz? They laid the groundwork for calculus in the 17th century, demonstrating how functions could be analyzed even when they weren’t explicitly defined. Math has quite the rich history, making it both fascinating and fun!

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