Let $$ f(x)=x^{2}+7 $$ and $$ g(x)=3 x+5 $$. Find $$ (g \circ f)(6) $$

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To find $$ (g \circ f)(6) $$, we first need to evaluate $$ f(6) $$ and then use that result to evaluate $$ g(f(6)) $$.

1. Calculate $$ f(6) $$:
   $$
   f(x) = x^2 + 7
   $$
   Substituting $$ x = 6 $$:
   $$
   f(6) = 6^2 + 7 = 36 + 7 = 43
   $$

2. Now, we need to evaluate $$ g(f(6)) = g(43) $$:
   $$
   g(x) = 3x + 5
   $$
   Substituting $$ x = 43 $$:
   $$
   g(43) = 3(43) + 5 = 129 + 5 = 134
   $$

Thus, $$ (g \circ f)(6) = g(f(6)) = g(43) = 134 $$.

The final answer is:
$$
\boxed{134}
$$
$$ (g \circ f)(6) = 134 $$

Let \( f(x)=x^{2}+7 \) and \( g(x)=3 x+5 \). Find \( (g \circ f)(6) \)

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