Question
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For the function \( g(x)=\frac{x+1}{x+5} \), solve the following inequality. \( g(x)>0 \)

Ask by Munoz Erickson. in the United States
Mar 20,2025

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Tutor-Verified Answer

Answer

The solution to \( g(x) > 0 \) is \( x < -5 \) or \( x > -1 \).

Solution

Solve the equation \( \frac{x+1}{x+5}>0 \). Solve the inequality by following steps: - step0: Solve the inequality by testing the values in the interval: \(\frac{x+1}{x+5}>0\) - step1: Find the domain: \(\frac{x+1}{x+5}>0,x\neq -5\) - step2: Set the numerator and denominator of \(\frac{x+1}{x+5}\) equal to 0\(:\) \(\begin{align}&x+1=0\\&x+5=0\end{align}\) - step3: Calculate: \(\begin{align}&x=-1\\&x=-5\end{align}\) - step4: Determine the test intervals: \(\begin{align}&x<-5\\&-5-1\end{align}\) - step5: Choose a value: \(\begin{align}&x_{1}=-6\\&x_{2}=-3\\&x_{3}=0\end{align}\) - step6: Test the chosen value: \(\begin{align}&x<-5\textrm{ }\textrm{is the solution}\\&-5-1\textrm{ }\textrm{is the solution}\end{align}\) - step7: The final solution is \(x \in \left(-\infty,-5\right)\cup \left(-1,+\infty\right):\) \(x \in \left(-\infty,-5\right)\cup \left(-1,+\infty\right)\) - step8: Check if the solution is in the defined range: \(x \in \left(-\infty,-5\right)\cup \left(-1,+\infty\right),x\neq -5\) - step9: Find the intersection: \(x \in \left(-\infty,-5\right)\cup \left(-1,+\infty\right)\) The solution to the inequality \( g(x) > 0 \) is \( x \in (-\infty, -5) \cup (-1, \infty) \).

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Bonus Knowledge

To solve the inequality \( g(x) > 0 \), we start by finding when the function \( g(x) = \frac{x + 1}{x + 5} \) is greater than zero. This fraction is positive when both the numerator and denominator are either both positive or both negative. 1. **Numerator**: \( x + 1 > 0 \) gives \( x > -1 \). 2. **Denominator**: \( x + 5 > 0 \) gives \( x > -5 \). Now, let's analyze the regions defined by these two critical points, \( -1 \) and \( -5 \). - Both numerator and denominator are positive for \( x > -1 \). - Both numerator and denominator are negative for \( x < -5 \). Thus, the solution to the inequality \( g(x) > 0 \) is \( x > -1 \) or \( x < -5 \). In interval notation, the solution is \( (-\infty, -5) \cup (-1, \infty) \). Remember to check for any values where the function is undefined; here \( g(x) \) is undefined at \( x = -5 \) but since we only care about when it's greater than zero, our intervals remain valid.

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