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Leap years occur in years that are divisible by 4. However, if the year ends in two zeros, it must be divisible by 400 in order to be a leap year. Determine whether the years 1798,2262 , and 800 are leap years. Was 1798 a leap year? Yes No

Ask by Sandoval Perkins. in the United States
Mar 10,2025

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Answer

\(1798\) is not a leap year.

Solution

**Step 1:** Check if the year \(1798\) is divisible by \(4\). We compute \(1798 \div 4\). \[ 1798 \div 4 = 449.5 \] Since the result is not an integer, \(1798\) is not divisible by \(4\). **Conclusion:** Because a leap year must be divisible by \(4\) (and for years ending in two zeros, further divisible by \(400\)), and \(1798\) fails the divisibility by \(4\) test, \(1798\) is not a leap year. **Answer:** No

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1798 is not a leap year because it is not divisible by 4. As per the leap year rules, only years that are divisible by 4 are considered leap years, and since 1798 fails this test, it remains a simple common year. For 2262, it is also not a leap year. Although it is divisible by 4, leap years must also pass the two-zero rule if applicable in cases like the year 800. However, since 2262 does not fulfill the criteria for simplicity in no century ending, 2262 is a common year too. In contrast, the year 800 is a leap year because it is divisible by both 4 and 400, fitting perfectly into the leap year guidelines!

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