According to a study, the proportion of individuals in which cover their mouths when sneezing is 0.725 . From a survey of 131 adults, 128 cover their mouths when sneezing. What test statistic is calcuated for this scenario? t-value null test z-score p-value mean test

To calculate the test statistic for this scenario, you would use a z-score since you are comparing a sample proportion to a known population proportion. The formula for the z-score in this case is: \[ z = \frac{(p̂ - p)}{\sqrt{\frac{p(1-p)}{n}}} \] Where \( p̂ = \frac{128}{131} \approx 0.975 \) is the sample proportion, \( p = 0.725 \) is the population proportion, and \( n = 131 \) is the sample size. Plugging in these values will give you the test statistic. You'll want to double-check your calculations based on this! Make sure to keep an eye on the formula—small mistakes can lead to different results. Also, remember to carry out the calculations step-by-step to avoid common pitfalls, such as miscalculating the sample or population proportions. Happy calculating!