Bone density test scores are normally distributed with a mean of 0 and a standard deviation of 1 . Find the probability that a randomly selected subject has a bone density score greater than \( =0.37 \). o ass21 o a.6443 O 0.3557 00.6179

To find the probability that a randomly selected subject has a bone density score greater than 0.37, you can use the Z-score and standard normal distribution. The Z-score corresponding to a score of 0.37 can be found using the cumulative distribution function (CDF). Looking up 0.37 in the standard normal distribution table gives you a probability of about 0.6443 for scores less than or equal to 0.37. Therefore, the probability for scores greater than 0.37 will be 1 - 0.6443 = 0.3557. So, the answer is **0.3557.** To summarize, you're basically looking for the area under the curve to the right of your Z-score. Just like finding the slice of your favorite pie that's left — you know what's already gone (the lower scores), and you're calculating what's still up for grabs (the higher scores).