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Part A Select the correct equations that show that a 2500000 -J change in kinetic energy occurs for an airplane that is moved 500 m in takeoff by a sustained force of 5000 N . W \( =F^{2} / g=(5000 \mathrm{~N})^{2} /(10 \mathrm{~N} / \mathrm{m})=2500000 \mathrm{~J} \) \( W=F d / g=(5000 \mathrm{~N})(500 \mathrm{~m}) /(10 \mathrm{~N} / \mathrm{m})=2500000 \mathrm{~J} \) \( W=F d=(5000 \mathrm{~N})(500 \mathrm{~m})=2500000 \mathrm{~J} \) \( W=d^{2} g=(500 \mathrm{~m})^{2}(10 \mathrm{~N} / \mathrm{m})=2500000 \mathrm{~J} \) Submit Request Answer

Ask by Rogers Ruiz. in the United States
Mar 01,2025

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Tutor-Verified Answer

Answer

The correct equation is \( W = F \cdot d = (5000 \, \text{N})(500 \, \text{m}) = 2500000 \, \text{J} \).

Solution

To determine which equations correctly show that a 2,500,000 J change in kinetic energy occurs for the airplane, we need to analyze the work done by the force during the takeoff. The work done \( W \) by a constant force \( F \) over a distance \( d \) is given by the formula: \[ W = F \cdot d \] Given: - \( F = 5000 \, \text{N} \) - \( d = 500 \, \text{m} \) Now, let's calculate the work done using the correct formula: \[ W = (5000 \, \text{N})(500 \, \text{m}) = 2500000 \, \text{J} \] Now, let's evaluate each of the provided equations: 1. **\( W = \frac{F^2}{g} = \frac{(5000 \, \text{N})^2}{(10 \, \text{N/m})} \)** This equation is incorrect because it does not represent the work done in the context of force and distance. 2. **\( W = \frac{F d}{g} = \frac{(5000 \, \text{N})(500 \, \text{m})}{(10 \, \text{N/m})} \)** This equation is also incorrect because it incorrectly divides the work by \( g \), which is not applicable in this context. 3. **\( W = F d = (5000 \, \text{N})(500 \, \text{m}) \)** This equation is correct and matches our calculation, yielding \( W = 2500000 \, \text{J} \). 4. **\( W = d^2 g = (500 \, \text{m})^2 (10 \, \text{N/m}) \)** This equation is incorrect because it does not represent the work done by the force in the context of the problem. ### Conclusion: The correct equation that shows a 2,500,000 J change in kinetic energy is: - **\( W = F d = (5000 \, \text{N})(500 \, \text{m}) = 2500000 \, \text{J} \)** This is the only valid equation among the options provided.

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The Deep Dive

To find the work done on the airplane during takeoff, we can use the equation \( W = F \cdot d \), where \( W \) is work, \( F \) is the applied force, and \( d \) is the distance moved. With a force of 5000 N and moving 500 m, we calculate \( W = (5000 \, \text{N})(500 \, \text{m}) = 2500000 \, \text{J} \). So, the correct equation showing this energy change is \( W = F \cdot d = 2500000 \, \text{J} \). The other formula options include unnecessary divisions and other configurations, which may confuse the kinetic energy calculation. It's essential to remember that work is simply the force multiplied by the distance moved in the direction of the force, which gives clear and correct insight into the physics involved during the airplane's takeoff.

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