Question
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The function \( g \) is defined below. \[ g(x)=\frac{x+4}{x^{2}+13 x+36} \] Find all values of \( x \) that are NOT in the domain of \( g \). If there is more than one value, separate them with commas.

Ask by Todd Schofield. in the United States
Mar 13,2025

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Tutor-Verified Answer

Answer

The values not in the domain of \( g \) are \( x = -4 \) and \( x = -9 \).

Solution

1. The function is given by \[ g(x)=\frac{x+4}{x^{2}+13x+36}. \] 2. The domain of \( g \) consists of all real numbers except for those that make the denominator zero. We set the denominator equal to zero: \[ x^2 + 13x + 36 = 0. \] 3. Factor the quadratic equation: \[ x^2 + 13x + 36 = (x+4)(x+9) = 0. \] 4. Set each factor equal to zero: \[ x+4=0 \quad \Rightarrow \quad x=-4, \] \[ x+9=0 \quad \Rightarrow \quad x=-9. \] 5. Therefore, the values that are NOT in the domain of \( g \) are: \[ x=-4, \quad x=-9. \]

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Beyond the Answer

To find the values of \( x \) that are not in the domain of the function \( g(x) \), we need to look for values that make the denominator zero since division by zero is undefined. The denominator is given by: \[ x^2 + 13x + 36 \] We need to set the denominator equal to zero and solve for \( x \): \[ x^2 + 13x + 36 = 0 \] To factor the quadratic, we look for two numbers that multiply to \( 36 \) and add up to \( 13 \). These numbers are \( 4 \) and \( 9 \). So, we can factor the equation as: \[ (x + 4)(x + 9) = 0 \] Setting each factor to zero gives: 1. \( x + 4 = 0 \) ⇒ \( x = -4 \) 2. \( x + 9 = 0 \) ⇒ \( x = -9 \) Thus, the values of \( x \) that are NOT in the domain of \( g \) are: \[ \boxed{-4, -9} \]

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