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Use the square root property to solve the equation. \( t^{2}=27 \)

Ask by Harris Ball. in the United States
Mar 01,2025

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Answer

The solutions are \( t = 3\sqrt{3} \) and \( t = -3\sqrt{3} \).

Solution

To solve the equation t² = 27 using the square root property, follow these steps: 1. Start with the equation:   t² = 27 2. Apply the square root property, which tells us that if t² = 27, then:   t = ±√27 3. Simplify √27 by factoring under the square root:   √27 = √(9 × 3) = √9 × √3 = 3√3 4. Thus, the solutions are:   t = 3√3 or t = -3√3 So, t = ±3√3 is the solution set.

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Beyond the Answer

To solve the equation \( t^{2} = 27 \) using the square root property, we take the square root of both sides. This gives us: \[ t = \pm \sqrt{27} \] Since \( \sqrt{27} \) can be simplified to \( 3\sqrt{3} \), the complete solution is: \[ t = 3\sqrt{3} \text{ or } t = -3\sqrt{3} \] So, the two solutions for the equation \( t^{2} = 27 \) are \( t = 3\sqrt{3} \) and \( t = -3\sqrt{3} \). And there you have it—two values of \( t \) waiting to be plugged into your math adventures!

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