Question
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For each expression, simplify if possible. If applicable, click on "Cannot be simplified". \( \frac{6 v+5}{5 v+6}=\square \) \( \frac{v-7}{-7+v}=\square \)

Ask by Bowers Hart. in the United States
Feb 26,2025

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Tutor-Verified Answer

Answer

The first expression simplifies to \( \frac{6}{5} - \frac{11}{5(v+6)} \). The second expression simplifies to 1.

Solution

Calculate or simplify the expression \( \frac{6v+5}{5v+6} \). Divide the polynomials by following steps: - step0: Using Long Division to Divide Polynomials: \(\frac{6v+5}{5v+6}\) - step1: Calculate: \(\frac{6}{5}+\frac{-\frac{11}{5}}{5v+6}\) Calculate or simplify the expression \( \frac{v-7}{-7+v} \). Simplify the expression by following steps: - step0: Solution: \(\frac{v-7}{-7+v}\) - step1: Reduce the fraction: \(1\) The simplified form of the first expression is \( \frac{6}{5} - \frac{11}{5(v+6)} \). The simplified form of the second expression is 1.

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The Deep Dive

The first expression \( \frac{6 v + 5}{5 v + 6} \) cannot be simplified further since there are no common factors to cancel out and both the numerator and denominator do not share a simple ratio. For the second expression \( \frac{v - 7}{-7 + v} \), you can rewrite the denominator as \( v - 7 \). This means it simplifies to \( \frac{v - 7}{v - 7} = 1 \) when \( v \neq 7 \). So, the simplified answer is \( 1 \) for \( v \neq 7 \).

Related Questions

ISCELÁNEA cribir, por simple inspección, el resultado de: \( \begin{array}{lll}(x+2)^{2} & \text { 14. }(x+y+1)(x-y-1) & \text { 27. }\left(2 a^{3}-5 b^{4}\right)^{2} \\ (x+2)(x+3) & \text { 15. }(1-a)(a+1) & \text { 28. }\left(a^{3}+12\right)\left(a^{3}-15\right) \\ (x+1)(x-1) & \text { 16. }(m-8)(m+12) & \text { 29. }\left(m^{2}-m+n\right)\left(n+m+m^{2}\right) \\ (x-1)^{2} & \text { 17. }\left(x^{2}-1\right)\left(x^{2}+3\right) & \text { 30. }\left(x^{4}+7\right)\left(x^{4}-11\right) \\ (n+3)(n+5) & \text { 18. }\left(x^{3}+6\right)\left(x^{3}-8\right) & \text { 31. }(11-a b)^{2} \\ (m-3)(m+3) & \text { 19. }\left(5 x^{3}+6 m^{4}\right)^{2} & \text { 32. }\left(x^{2} y^{3}-8\right)\left(x^{2} y^{3}+6\right) \\ (a+b-1)(a+b+1) & \text { 20. }\left(x^{4}-2\right)\left(x^{4}+5\right) & \text { 33. }(a+b)(a-b)\left(a^{2}-b^{2}\right) \\ (1+b)^{3} & \text { 21. }(1-a+b)(b-a-1) & \text { 34. }(x+1)(x-1)\left(x^{2}-2\right) \\ \left(a^{2}+4\right)\left(a^{2}-4\right) & \text { 22. }\left(a^{x}+b^{n}\right)\left(a^{x}-b^{n}\right) & \text { 35. }(a+3)\left(a^{2}+9\right)(a-3) \\ \left(3 a b-5 x^{2}\right)^{2} & \text { 23. }\left(x^{a+1}-8\right)\left(x^{a+1}+9\right) & \text { 36. }(x+5)(x-5)\left(x^{2}+1\right) \\ (a b+3)(3-a b) & \text { 24. }\left(a^{2} b^{2}+c^{2}\right)\left(a^{2} b^{2}-c^{2}\right) & \text { 37. }(a+1)(a-1)(a+2)(a-2) \\ (1-4 a x)^{2} & \text { 25. }(2 a+x)^{3} & \text { 36. }\left(x^{2}-11\right)\left(x^{2}-2\right)\end{array} \) \( \left(a^{2}+8\right)\left(a^{2}-7\right) \)
Algebra Mexico Feb 26, 2025
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