Multiply. $$ \frac{x^{2}+2 x-3}{4 x+8} \cdot \frac{x+2}{x^{2}-3 x+2} $$ Simplify your answer as much as possible.

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Calculate or simplify the expression $$ \frac{x^{2}+2x-3}{4x+8} \cdot \frac{x+2}{x^{2}-3x+2} $$.
Simplify the expression by following steps:
- step0: Solution:
  $$\frac{x^{2}+2x-3}{4x+8}	imes \frac{x+2}{x^{2}-3x+2}$$
- step1: Rewrite the expression:
  $$\frac{\left(x-1ight)\left(x+3ight)}{4x+8}	imes \frac{x+2}{\left(x-1ight)\left(x-2ight)}$$
- step2: Reduce the fraction:
  $$\frac{x+3}{4x+8}	imes \frac{x+2}{x-2}$$
- step3: Rewrite the expression:
  $$\frac{x+3}{4\left(x+2ight)}	imes \frac{x+2}{x-2}$$
- step4: Reduce the fraction:
  $$\frac{x+3}{4}	imes \frac{1}{x-2}$$
- step5: Multiply the terms:
  $$\frac{x+3}{4\left(x-2ight)}$$
- step6: Simplify:
  $$\frac{x+3}{4x-8}$$
The simplified form of the expression $$\frac{x^{2}+2x-3}{4x+8} \cdot \frac{x+2}{x^{2}-3x+2}$$ is $$\frac{x+3}{4x-8}$$.
The simplified form is $$ \frac{x+3}{4x-8} $$.

Multiply.

Simplify your answer as much as possible.

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Multiply. Simplify your answer as much as possible.