Answer
**7. Subtract \(\frac{9}{10}\) and \(\frac{4}{10}\):**
\[
\frac{9}{10} - \frac{4}{10} = \frac{5}{10} = \frac{1}{2}
\]
**8. Solve for the blank in \(\frac{8}{7} - \,\,\underline{\quad} \,\, = \frac{3}{7}\):**
\[
\frac{8}{7} - \frac{5}{7} = \frac{3}{7}
\]
**9. Solve for the blank in \(\frac{8}{10} - \,\,\underline{\quad} \,\, = \frac{3}{10}\):**
\[
\frac{8}{10} - \frac{5}{10} = \frac{3}{10}
\]
**10. Subtract \(\frac{4}{6}\) and \(\frac{3}{6}\):**
\[
\frac{4}{6} - \frac{3}{6} = \frac{1}{6}
\]
**11. Total apples bought by Sam and John:**
\[
\frac{3}{8} + \frac{5}{8} = 1 \text{ kg}
\]
**12. Fraction of peanuts Shaina ate:**
\[
\frac{4}{5} - \frac{2}{5} = \frac{2}{5}
\]
**13. Pie eaten by Rahul and his friend:**
\[
\frac{3}{8} + \frac{2}{8} = \frac{5}{8} \text{ eaten}, \quad \frac{3}{8} \text{ left}
\]
**14. Solve for the blank in \(\frac{4}{10} - \,\,\underline{\quad} \,\, = \frac{2}{10}\):**
\[
\frac{4}{10} - \frac{2}{10} = \frac{2}{10} = \frac{1}{5}
\]
**15. Solve for the blank in \(\underline{\quad} - \frac{6}{9} = \frac{3}{9}\):**
\[
1 - \frac{6}{9} = \frac{3}{9}
\]
Solution
**7. Subtract \(\frac{9}{10}\) and \(\frac{4}{10}\).**
We compute:
\[
\frac{9}{10} - \frac{4}{10} = \frac{9-4}{10} = \frac{5}{10} = \frac{1}{2}
\]
**8. Solve for the blank in \(\frac{8}{7} - \,\,\underline{\quad} \,\, = \frac{3}{7}\).**
Let the unknown fraction be \(x\). Then:
\[
\frac{8}{7} - x = \frac{3}{7}
\]
Subtract \(\frac{3}{7}\) from \(\frac{8}{7}\):
\[
x = \frac{8}{7} - \frac{3}{7} = \frac{5}{7}
\]
**9. Solve for the blank in \(\frac{8}{10} - \,\,\underline{\quad} \,\, = \frac{3}{10}\).**
Let the unknown fraction be \(x\). Then:
\[
\frac{8}{10} - x = \frac{3}{10}
\]
Subtract \(\frac{3}{10}\) from \(\frac{8}{10}\):
\[
x = \frac{8}{10} - \frac{3}{10} = \frac{5}{10} = \frac{1}{2}
\]
**10. Subtract \(\frac{4}{6}\) and \(\frac{3}{6}\).**
We compute:
\[
\frac{4}{6} - \frac{3}{6} = \frac{4-3}{6} = \frac{1}{6}
\]
**11. Sam bought \(\frac{3}{8}\) kg of apples and John bought \(\frac{5}{8}\) kg of apples. What was the total quantity of apple that was bought.**
We add the two amounts:
\[
\frac{3}{8} + \frac{5}{8} = \frac{3+5}{8} = \frac{8}{8} = 1 \text{ kg}
\]
**12. Shaina got \(\frac{4}{5}\) of a packet of peanuts. After she ate some, \(\frac{2}{5}\) of the peanuts remained. What fraction of the peanuts did she eat?**
The amount eaten is the original amount minus the remaining amount:
\[
\frac{4}{5} - \frac{2}{5} = \frac{4-2}{5} = \frac{2}{5}
\]
**13. Rahul and his friend shared a pie. Rahul ate \(\frac{3}{8}\) of the pie and his friend ate \(\frac{2}{8}\) of the pie. How much pie did they eat altogether and how much was left?**
First, find the total eaten:
\[
\frac{3}{8} + \frac{2}{8} = \frac{3+2}{8} = \frac{5}{8}
\]
The remaining pie is:
\[
1 - \frac{5}{8} = \frac{8}{8} - \frac{5}{8} = \frac{3}{8}
\]
**14. Solve for the blank in \(\frac{4}{10} - \,\,\underline{\quad} \,\, = \frac{2}{10}\).**
Let the unknown fraction be \(x\). Then:
\[
\frac{4}{10} - x = \frac{2}{10}
\]
Subtract \(\frac{2}{10}\) from \(\frac{4}{10}\):
\[
x = \frac{4}{10} - \frac{2}{10} = \frac{2}{10} = \frac{1}{5}
\]
**15. Solve for the blank in \(\underline{\quad} - \frac{6}{9} = \frac{3}{9}\).**
Let the unknown fraction be \(x\). Then:
\[
x - \frac{6}{9} = \frac{3}{9}
\]
Add \(\frac{6}{9}\) to both sides:
\[
x = \frac{3}{9} + \frac{6}{9} = \frac{9}{9} = 1
\]
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