Remember that you can use inverse operations to solve equations. For \( 1-3 \), solve. 1. \( 4+2+h=10 \) 2. \( 4 x-3=17 \) 3. \( (v-8) \div 12=2 \)
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To find the value of \( h \) in the equation \( 4 + 2 + h = 10 \), first combine the numbers on the left side to get \( 6 + h = 10 \). Now, use the inverse operation: subtract 6 from both sides to isolate \( h \). Thus, \( h = 10 - 6 \) which simplifies to \( h = 4 \). For the equation \( 4x - 3 = 17 \), start by adding 3 to both sides to get \( 4x = 20 \). Now, divide both sides by 4 to solve for \( x \), yielding \( x = 20 ÷ 4 \), which gives you \( x = 5 \). To solve \( (v - 8) \div 12 = 2 \), multiply both sides by 12 to eliminate the division, resulting in \( v - 8 = 24 \). Finally, add 8 to both sides to find \( v = 24 + 8 \), hence \( v = 32 \).