Solve the equation given by completing the square. \( 5 x^{2}+30 x+25=0 \) [Hint: Divide by 5 first] \( x=\square \)
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First, let's divide the entire equation by 5 to simplify it: \[ x^2 + 6x + 5 = 0 \] Next, we can move the constant term to the right side: \[ x^2 + 6x = -5 \] Now, we want to complete the square. To do this, take half of the coefficient of \(x\) (which is 6), square it (which gives us 9), and add it to both sides: \[ x^2 + 6x + 9 = 4 \] Now, we can express the left side as a perfect square: \[ (x + 3)^2 = 4 \] Taking the square root of both sides, we get: \[ x + 3 = \pm 2 \] Now, let's solve for \(x\): 1. \(x + 3 = 2\) leads to \(x = -1\) 2. \(x + 3 = -2\) leads to \(x = -5\) So, the solutions are: \[ x = -1 \quad \text{and} \quad x = -5 \]