Question
A population of values has a normal distribution with \( \mu=204.2 \) and \( \sigma=24.3 \). You intend to draw a random sample of size \( n=184 \). What is the mean of the distribution of sample means? \( \mu_{x}=\square \) What is the standard deviation of the distribution of sample means? (Report answer accurate to 2 decimal places.) \( \sigma_{x}=\square \)
Ask by Love Moran. in the United States
Mar 16,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The mean of the distribution of sample means is 204.2, and the standard deviation is 1.79.
Solution
1. The distribution of sample means has the same mean as the population. Thus,
\[
\mu_{x} = 204.2.
\]
2. The standard deviation of the sample means (also known as the standard error) is given by
\[
\sigma_{x} = \frac{\sigma}{\sqrt{n}}.
\]
Substituting the given values,
\[
\sigma_{x} = \frac{24.3}{\sqrt{184}}.
\]
3. First, calculate \(\sqrt{184}\):
\[
\sqrt{184} \approx 13.56466.
\]
4. Then,
\[
\sigma_{x} \approx \frac{24.3}{13.56466} \approx 1.79.
\]
The final answers are:
\[
\mu_{x} = 204.2 \quad \text{and} \quad \sigma_{x} = 1.79.
\]
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The Deep Dive
The mean of the distribution of sample means, often referred to as the sampling distribution, is the same as the mean of the population distribution. So, in this case, \( \mu_{x} = 204.2 \). To find the standard deviation of the distribution of sample means (also known as the standard error), you use the formula: \[ \sigma_{x} = \frac{\sigma}{\sqrt{n}} = \frac{24.3}{\sqrt{184}} \approx 1.77 \] So, \( \sigma_{x} \approx 1.77 \).