Solving a quadratic equation using the square root properyy. -racu.. Solve \( (w+4)^{2}-9=0 \), where \( w \) is a real number. Simplify your answer as much as possible. If there is more than one solution, separate them with commas. If there is no solution, click "No solution." \( w=\square \)

To solve the equation \( (w+4)^{2}-9=0 \), we first isolate the squared term. Adding 9 to both sides gives us \( (w+4)^{2} = 9 \). We can now apply the square root property, which leads us to take the square root of both sides: \( w+4 = 3 \) or \( w+4 = -3 \). Now, solving these two equations separately: 1. For \( w + 4 = 3 \): \[ w = 3 - 4 \implies w = -1 \] 2. For \( w + 4 = -3 \): \[ w = -3 - 4 \implies w = -7 \] Thus, the solutions are \( w = -1, -7 \).