Let $$ f(x)=\frac{2 x^{2}-9 x+9}{3 x^{2}-14 x+8} $$ This function has: 1) Ay intercept at the point $$ \left(0, \frac{9}{8}\right) $$ 2) $$ x $$ intercepts at the point(s) $$ \left(\frac{3}{2}, 0\right),(3,0) $$ 3) Vertical asymptotes at $$ x= $$

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To find the vertical asymptotes of the function $$ f(x) = \frac{2x^2 - 9x + 9}{3x^2 - 14x + 8} $$, we need to determine the values of $$ x $$ for which the denominator of the function is equal to zero.

The denominator of the function is $$ 3x^2 - 14x + 8 $$. To find the values of $$ x $$ for which the denominator is equal to zero, we need to solve the equation $$ 3x^2 - 14x + 8 = 0 $$.

Let's solve the equation $$ 3x^2 - 14x + 8 = 0 $$ to find the vertical asymptotes of the function.
Solve the quadratic equation by following steps:
- step0: Solve by factoring:
  $$3x^{2}-14x+8=0$$
- step1: Factor the expression:
  $$\left(x-4ight)\left(3x-2ight)=0$$
- step2: Separate into possible cases:
  $$\begin{align}&x-4=0\&3x-2=0\end{align}$$
- step3: Solve the equation:
  $$\begin{align}&x=4\&x=\frac{2}{3}\end{align}$$
- step4: Rewrite:
  $$x_{1}=\frac{2}{3},x_{2}=4$$
The solutions to the equation $$3x^2 - 14x + 8 = 0$$ are $$x = \frac{2}{3}$$ and $$x = 4$$.

Therefore, the vertical asymptotes of the function $$ f(x) = \frac{2x^2 - 9x + 9}{3x^2 - 14x + 8} $$ are at $$ x = \frac{2}{3} $$ and $$ x = 4 $$.
The vertical asymptotes of the function are at $$ x = \frac{2}{3} $$ and $$ x = 4 $$.

Let
This function has:

Ay intercept at the point

intercepts at the point(s)

Vertical asymptotes at

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