Factor \( 4 x^{2}-11 x+6 \) \( (2 x+3)(2 x+2) \) \( (4 x-3)(x-2) \) \( (4 x+2)(x-3) \) Prime

To factor \( 4 x^{2}-11 x+6 \), we can begin by looking for two numbers that multiply to \( 4 \times 6 = 24 \) and add to \(-11\). The numbers \(-8\) and \(-3\) fit this requirement! We can then rewrite the middle term and factor by grouping. The correct factorization is \( (4x - 3)(x - 2) \), where multiplying these two binomials gives us back the original quadratic expression. So, no matter which path you take, keep those magic numbers in mind! In the world of algebra, factoring quadratics is all about recognizing patterns and relationships! You'll often encounter quadratics that can be factored using techniques like grouping, completing the square, or even the quadratic formula. Practicing these methods can turn the intimidating world of polynomials into a fun puzzle adventure!