37) \( 4 u v+14 u^{2}+12 v+42 v \)

To simplify the given expression, \( 4uv + 14u^2 + 12v + 42v \), we start by combining like terms. First, add the coefficients of \( v \): \( 12v + 42v = 54v \). Thus, our expression becomes: \( 4uv + 14u^2 + 54v \). This is the simplified form, and it's clear now how each term relates to \( u \) and \( v \). It's a polynomial in two variables, where you can easily identify the contribution of each term based on the values of \( u \) and \( v \). If you're looking to factor this further, you could look for common factors in pairs of the terms. For example, we can factor \( 2 \) out of \( 14u^2 + 54v \) to get \( 2(7u^2 + 27v) \), but factoring the entire expression may require further manipulation depending on the context.