5 Ed has two dogs. The smaller dog weighs \( 8 \frac{1}{3} \) pounds. The larger dog weighs \( 1 \frac{1}{2} \) times as much as the smaller dog. How much does the larger dog weigh?
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To find the weight of the larger dog, you first need to convert the weight of the smaller dog into an improper fraction. The smaller dog's weight is \( 8 \frac{1}{3} \) pounds, which can be converted as follows: \( 8 \frac{1}{3} = \frac{25}{3} \). Now, since the larger dog weighs \( 1 \frac{1}{2} \) times the smaller dog's weight, we convert \( 1 \frac{1}{2} \) into an improper fraction: \( 1 \frac{1}{2} = \frac{3}{2} \). Now, you can calculate the weight of the larger dog by multiplying the weight of the smaller dog by \( \frac{3}{2} \): \[ \text{Weight of larger dog} = \frac{25}{3} \times \frac{3}{2} = \frac{25 \times 3}{3 \times 2} = \frac{25}{2} = 12 \frac{1}{2} \text{ pounds}. \] So, the larger dog weighs \( 12 \frac{1}{2} \) pounds.
