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Summarize all pertinent information obtained by applying the graphing strategy and sketch the graph of \( y=f(x) \). \( f(x)=\frac{x^{2}+9 x+18}{x^{2}+6 x+9} \) A. The \( y \)-intercept(s) is/are at \( y=\square \) (Type an integer or a simplified fraction. Use a comma to separate answers as needed.) B. There are no y-intercepts. Find any horizontal asymptotes of \( f(x) \). Select the correct choice below and, if necessary, fill in the answer box(es) to complete your choice. A. The function has one horizontal asymptote, \( \square . ~ \) (Type an equation.) B. The function has two horizontal asymptotes. The top asymptote is \( \square \) and the bottom asymptote is \( \square \). (Type equations.) C. There are no horizontal asymptotes.

Ask by Ball Hammond. in the United States
Mar 18,2025

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- A. The \( y \)-intercept is at \( y=2 \). - A. The function has one horizontal asymptote, \( y=1 \).

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Bonus Knowledge

To find the \( y \)-intercept, set \( x=0 \) in the function \( f(x)=\frac{x^{2}+9 x+18}{x^{2}+6 x+9} \). This gives \( f(0)=\frac{0^{2}+9(0)+18}{0^{2}+6(0)+9}=\frac{18}{9}=2 \). Thus, the \( y \)-intercept is at \( y=2 \). For horizontal asymptotes, we look at the degrees of the numerator and denominator. Both are quadratic (degree 2), so we take the leading coefficients. The coefficient of \( x^2 \) in the numerator is 1 and in the denominator is also 1. Therefore, the horizontal asymptote is \( y=\frac{1}{1}=1 \).

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