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15. What is the value of \( y \) in the following system of equations? \[ \begin{array}{l}y=4 x-12 \\ y=10 x-42\end{array} \]

Ask by Moreno Thornton. in the United States
Jan 31,2025

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Answer

\( y = 8 \)

Solution

To find the value of \( y \) in the given system of equations: \[ \begin{cases} y = 4x - 12 \\ y = 10x - 42 \end{cases} \] We can solve this system using the **substitution method** since both equations are already solved for \( y \). 1. **Set the two expressions for \( y \) equal to each other:** \[ 4x - 12 = 10x - 42 \] 2. **Solve for \( x \):** First, subtract \( 4x \) from both sides to get the \( x \)-terms on one side: \[ -12 = 6x - 42 \] Next, add \( 42 \) to both sides to isolate the term with \( x \): \[ 30 = 6x \] Now, divide both sides by \( 6 \): \[ x = 5 \] 3. **Substitute \( x = 5 \) back into one of the original equations to find \( y \).** We'll use the first equation: \[ y = 4x - 12 \] Plugging in \( x = 5 \): \[ y = 4(5) - 12 = 20 - 12 = 8 \] **So, the value of \( y \) is 8.**

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To find the value of \( y \) in the given system of equations, we can set the two equations equal to each other since both are equal to \( y \): \[ 4x - 12 = 10x - 42 \] Now, let's solve for \( x \): 1. Rearranging gives: \[ -12 + 42 = 10x - 4x \] \[ 30 = 6x \] \[ x = 5 \] Now we can substitute \( x \) back into one of the original equations to find \( y \). Let's use the first equation: \[ y = 4(5) - 12 \] \[ y = 20 - 12 \] \[ y = 8 \] Therefore, the value of \( y \) is \( 8 \).

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