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The graph of \( y=x^{2} \) is shown on each grid in parts (a) and (b) below. (a) Use transformations to get the graph of \( y=(2 x)^{2} \). (a)

Ask by Huff Simmons. in the United States
Mar 14,2025

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Answer

To get the graph of \( y = (2x)^2 \) from \( y = x^2 \), compress the graph horizontally by a factor of 2.

Solution

To transform the graph of \( y = x^2 \) to the graph of \( y = (2x)^2 \), we can follow these steps: 1. **Identify the transformation**: The expression \( (2x)^2 \) can be rewritten as \( 4x^2 \). This indicates that we are scaling the input \( x \) by a factor of 2. 2. **Horizontal Scaling**: The transformation \( y = (2x)^2 \) means that for every \( x \) value, we are effectively compressing the graph horizontally by a factor of 2. This is because the input \( x \) is multiplied by 2, which means that the graph will reach the same \( y \) values at half the \( x \) values. 3. **Graphing the Transformation**: - The vertex of the original graph \( y = x^2 \) is at the point (0, 0). - For the transformed graph \( y = (2x)^2 \), we can find some key points: - When \( x = 0 \), \( y = (2 \cdot 0)^2 = 0 \) → point (0, 0) - When \( x = 0.5 \), \( y = (2 \cdot 0.5)^2 = 1 \) → point (0.5, 1) - When \( x = 1 \), \( y = (2 \cdot 1)^2 = 4 \) → point (1, 4) - When \( x = -0.5 \), \( y = (2 \cdot -0.5)^2 = 1 \) → point (-0.5, 1) - When \( x = -1 \), \( y = (2 \cdot -1)^2 = 4 \) → point (-1, 4) 4. **Conclusion**: The graph of \( y = (2x)^2 \) will be a vertically stretched version of the graph of \( y = x^2 \) that is also horizontally compressed. The shape remains a parabola, but it will be narrower than the original graph. In summary, the transformation from \( y = x^2 \) to \( y = (2x)^2 \) involves a horizontal compression by a factor of 2.

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To get the graph of \( y=(2x)^{2} \) from \( y=x^{2} \), you first apply a horizontal compression by a factor of 2. This means that every point on the original graph moves closer to the y-axis, effectively halving the x-coordinates. The result is the graph of \( y=(2x)^{2} \), which appears steeper than \( y=x^{2} \), maintaining its vertex at the origin but reaching higher values of y more quickly as x increases. Now, if you were to sketch it out, you'd see that though both graphs are "U" shaped, the new graph \( y=(2x)^{2} \) is narrower and rises faster than the original \( y=x^{2} \). Try comparing specific points; for instance, while \( x=1 \) gives \( y=1 \) in the original graph, \( x=0.5 \) gives \( y=1 \) in the transformed graph! This hands-on comparison really highlights the transformation effect!

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