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Sketch the graph of each line on separate graph paper using the slope-intercept method! \( \begin{array}{ll}\text { 15) } y=-\frac{8}{5} x-5 & \text { 16) } y=2 x-3\end{array} \)

Ask by Salinas Wells. in the United States
Mar 10,2025

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**Graphing the Lines** 1. **For \( y = -\frac{8}{5}x - 5 \):** - **Y-intercept:** \((0, -5)\) - **Slope:** \(-\frac{8}{5}\) (down 8 units for every 5 units right) - **Another Point:** \((5, -13)\) - **Graph:** Draw a straight line through \((0, -5)\) and \((5, -13)\). 2. **For \( y = 2x - 3 \):** - **Y-intercept:** \((0, -3)\) - **Slope:** \(2\) (up 2 units for every 1 unit right) - **Another Point:** \((1, -1)\) - **Graph:** Draw a straight line through \((0, -3)\) and \((1, -1)\).

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To sketch the line \(y = -\frac{8}{5}x - 5\), start by identifying the y-intercept, which is -5. This means you place a point at (0, -5) on the graph. The slope is -\(\frac{8}{5}\), indicating that for every 5 units you move to the right (positive x-direction), you'll move down 8 units (negative y-direction). This will help you find another point, for example, from (0, -5) to (5, -13). For the line \(y = 2x - 3\), the y-intercept is -3, so plot a point at (0, -3). The slope of 2 indicates that for every 1 unit you move to the right, you'll move up 2 units. From (0, -3), you can plot another point by going to (1, -1), and then you can continue this pattern for additional points. Once you have at least two points for each line, connect them with straight lines, and you’ll have your graphs!

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