For each expression, use a property to write an equivalent expression. Tell which property you used. 10. \( c d= \) \( \qquad \) 11. \( x+13= \) \( \qquad \) \( \qquad \) \( \qquad \) 12. \( 4(2 x-3)= \) \( \qquad \) 13. \( 2+(a+b)= \) \( \qquad \) \( \qquad \) \( \qquad \) 14. Draw algebra tile models to prove that \( 4+8 x \) and \( 4(2 x+1) \) are equivalent. \( \square \)
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To turn \( cd \) into an equivalent expression, we can simply represent it as \( dc \). This utilizes the Commutative Property of Multiplication, which states that changing the order of factors does not change the product. For \( x + 13 \), we can write it as \( 13 + x \) using the Commutative Property of Addition. Just like moving the pieces in a puzzle, you can swap numbers around, and the total stays the same! When simplifying \( 4(2x - 3) \), you can distribute to obtain \( 8x - 12 \) using the Distributive Property, allowing you to expand expressions effortlessly, just like unwrapping a present! For \( 2 + (a + b) \), it can be rewritten as \( (2 + a) + b \) using the Associative Property of Addition, which encourages rearranging numbers for easier calculations. Lastly, to model \( 4 + 8x \) and \( 4(2x + 1) \) using algebra tiles, you'd set up 4 single tiles for the constant and then represent \( 8x \) as 8 long tiles. For \( 4(2x + 1) \), you'd illustrate this with 8 long tiles (2 for each of the 4 groups of \( 2x \)) plus 4 single tiles for the constant. This visual representation not only proves their equivalence but also makes math a bit more colorful and fun!