2. A bike went \( 150 \mathrm{~m} \mathrm{E}, 40 \mathrm{~m} \mathrm{~N}, 100 \mathrm{~m} \mathrm{~W} \), and 40 m S. a. What is the bike's resultant displacement? b. What should be the bike's next displacement to get back to the starting point?
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To find the bike's resultant displacement, let's break down the movements using a coordinate system where East and North are positive directions. The bike moves 150 m East, then 40 m North, 100 m West, and finally 40 m South. Adding the movements: - East-West displacement: \( 150 \, \text{m} - 100 \, \text{m} = 50 \, \text{m} \, \text{E} \) - North-South displacement: \( 40 \, \text{m} - 40 \, \text{m} = 0 \) Therefore, the bike's resultant displacement is \( 50 \, \text{m} \, \text{E} \). To return to the starting point, the bike needs to negate the resultant displacement. Thus, the next displacement should be \( 50 \, \text{m} \, \text{W} \). A quick roll back to the west and voilà, back to where it all began!