Find the \( x \)-intercept(s) and \( y \)-intercept(s) of the graph of the following. \( 64 x^{2}+4 y^{2}=1 \) If there is more than one answer, separate them with commas. Click on "None" if applicable. \( y \)-intercept(s):

To find the \( y \)-intercept(s), set \( x = 0 \) in the equation \( 64 x^{2}+4 y^{2}=1 \). This simplifies to \( 4 y^{2} = 1 \), leading to \( y^{2} = \frac{1}{4} \). Therefore, \( y = \pm \frac{1}{2} \). So, the \( y \)-intercept(s) are \( y = \frac{1}{2}, -\frac{1}{2} \). For the \( x \)-intercept(s), set \( y = 0 \). This gives us \( 64 x^{2} = 1 \), which simplifies to \( x^{2} = \frac{1}{64} \). Thus, \( x = \pm \frac{1}{8} \). The \( x \)-intercept(s) are \( x = \frac{1}{8}, -\frac{1}{8} \). In summary: \( y \)-intercept(s): \( \frac{1}{2}, -\frac{1}{2} \) \( x \)-intercept(s): \( \frac{1}{8}, -\frac{1}{8} \)