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13) \( 4 m^{2}-9 m-9 \) 15) \( 6 p^{2}-11 p-7 \) 17) \( 4 r^{2}+3 r-7 \) 19) \( 3 x^{2}+10 x-8 \) 21) \( 2 y^{2}+15 y+7 \) 23) \( 4 x^{2}+16 x+16 \) 25) \( 10 x^{3}+15 x^{2}-10 x \) 27) \( 5 t^{2}+15 t+10 \) 29) \( 7 x^{2}-2 x y-5 y^{2} \)

Ask by Dawson Cox. in the United States
Mar 12,2025

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Answer

Here are the factorizations: 1. \( 4 m^{2}-9 m-9 = (m-3)(4m+3) \) 2. \( 6 p^{2}-11 p-7 = (2p+1)(3p-7) \) 3. \( 4 r^{2}+3 r-7 = (r-1)(4r+7) \) 4. \( 3 x^{2}+10 x-8 = (x+4)(3x-2) \) 5. \( 2 y^{2}+15 y+7 = (y+7)(2y+1) \) 6. \( 4 x^{2}+16 x+16 = 4(x+2)^{2} \) 7. \( 10 x^{3}+15 x^{2}-10 x = 5x(x+2)(2x-1) \) 8. \( 5 t^{2}+15 t+10 = 5(t+1)(t+2) \) 9. \( 7 x^{2}-2 x y-5 y^{2} = (7x+5y)(x-y) \)

Solution

Factor the expression by following steps: - step0: Factor: \(6p^{2}-11p-7\) - step1: Rewrite the expression: \(6p^{2}+\left(-14+3\right)p-7\) - step2: Calculate: \(6p^{2}-14p+3p-7\) - step3: Rewrite the expression: \(2p\times 3p-2p\times 7+3p-7\) - step4: Factor the expression: \(2p\left(3p-7\right)+3p-7\) - step5: Factor the expression: \(\left(2p+1\right)\left(3p-7\right)\) Factor the expression \( 7 x^{2}-2 x y-5 y^{2 \). Factor the expression by following steps: - step0: Factor: \(7x^{2}-2xy-5y^{2}\) - step1: Rewrite the expression: \(7x^{2}+\left(-7+5\right)xy-5y^{2}\) - step2: Calculate: \(7x^{2}-7xy+5yx-5y^{2}\) - step3: Rewrite the expression: \(7x\times x-7xy+5yx-5y\times y\) - step4: Factor the expression: \(7x\left(x-y\right)+5y\left(x-y\right)\) - step5: Factor the expression: \(\left(7x+5y\right)\left(x-y\right)\) Factor the expression \( 3 x^{2}+10 x-8 \). Factor the expression by following steps: - step0: Factor: \(3x^{2}+10x-8\) - step1: Rewrite the expression: \(3x^{2}+\left(-2+12\right)x-8\) - step2: Calculate: \(3x^{2}-2x+12x-8\) - step3: Rewrite the expression: \(x\times 3x-x\times 2+4\times 3x-4\times 2\) - step4: Factor the expression: \(x\left(3x-2\right)+4\left(3x-2\right)\) - step5: Factor the expression: \(\left(x+4\right)\left(3x-2\right)\) Factor the expression \( 4 m^{2}-9 m-9 \). Factor the expression by following steps: - step0: Factor: \(4m^{2}-9m-9\) - step1: Rewrite the expression: \(4m^{2}+\left(3-12\right)m-9\) - step2: Calculate: \(4m^{2}+3m-12m-9\) - step3: Rewrite the expression: \(m\times 4m+m\times 3-3\times 4m-3\times 3\) - step4: Factor the expression: \(m\left(4m+3\right)-3\left(4m+3\right)\) - step5: Factor the expression: \(\left(m-3\right)\left(4m+3\right)\) Factor the expression \( 4 x^{2}+16 x+16 \). Factor the expression by following steps: - step0: Factor: \(4x^{2}+16x+16\) - step1: Factor the expression: \(4\left(x+2\right)^{2}\) Factor the expression \( 4 r^{2}+3 r-7 \). Factor the expression by following steps: - step0: Factor: \(4r^{2}+3r-7\) - step1: Rewrite the expression: \(4r^{2}+\left(7-4\right)r-7\) - step2: Calculate: \(4r^{2}+7r-4r-7\) - step3: Rewrite the expression: \(r\times 4r+r\times 7-4r-7\) - step4: Factor the expression: \(r\left(4r+7\right)-\left(4r+7\right)\) - step5: Factor the expression: \(\left(r-1\right)\left(4r+7\right)\) Factor the expression \( 2 y^{2}+15 y+7 \). Factor the expression by following steps: - step0: Factor: \(2y^{2}+15y+7\) - step1: Rewrite the expression: \(2y^{2}+\left(1+14\right)y+7\) - step2: Calculate: \(2y^{2}+y+14y+7\) - step3: Rewrite the expression: \(y\times 2y+y+7\times 2y+7\) - step4: Factor the expression: \(y\left(2y+1\right)+7\left(2y+1\right)\) - step5: Factor the expression: \(\left(y+7\right)\left(2y+1\right)\) Factor the expression \( 5 t^{2}+15 t+10 \). Factor the expression by following steps: - step0: Factor: \(5t^{2}+15t+10\) - step1: Rewrite the expression: \(5t^{2}+5\times 3t+5\times 2\) - step2: Factor the expression: \(5\left(t^{2}+3t+2\right)\) - step3: Factor the expression: \(5\left(t+1\right)\left(t+2\right)\) Factor the expression \( 10 x^{3}+15 x^{2}-10 x \). Factor the expression by following steps: - step0: Factor: \(10x^{3}+15x^{2}-10x\) - step1: Rewrite the expression: \(5x\times 2x^{2}+5x\times 3x-5x\times 2\) - step2: Factor the expression: \(5x\left(2x^{2}+3x-2\right)\) - step3: Factor the expression: \(5x\left(x+2\right)\left(2x-1\right)\) Here are the factorizations for the given expressions: 1. **For \( 4 m^{2}-9 m-9 \)**: \[ 4 m^{2}-9 m-9 = (m-3)(4m+3) \] 2. **For \( 6 p^{2}-11 p-7 \)**: \[ 6 p^{2}-11 p-7 = (2p+1)(3p-7) \] 3. **For \( 4 r^{2}+3 r-7 \)**: \[ 4 r^{2}+3 r-7 = (r-1)(4r+7) \] 4. **For \( 3 x^{2}+10 x-8 \)**: \[ 3 x^{2}+10 x-8 = (x+4)(3x-2) \] 5. **For \( 2 y^{2}+15 y+7 \)**: \[ 2 y^{2}+15 y+7 = (y+7)(2y+1) \] 6. **For \( 4 x^{2}+16 x+16 \)**: \[ 4 x^{2}+16 x+16 = 4(x+2)^{2} \] 7. **For \( 10 x^{3}+15 x^{2}-10 x \)**: \[ 10 x^{3}+15 x^{2}-10 x = 5x(x+2)(2x-1) \] 8. **For \( 5 t^{2}+15 t+10 \)**: \[ 5 t^{2}+15 t+10 = 5(t+1)(t+2) \] 9. **For \( 7 x^{2}-2 x y-5 y^{2} \)**: \[ 7 x^{2}-2 x y-5 y^{2} = (7x+5y)(x-y) \] These factorizations simplify the expressions into products of binomials or polynomials. If you have any further questions or need additional assistance, feel free to ask!

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The Deep Dive

Got some quadratic polynomials and a cubic one to factor? Let's dive into the fun world of factorization! Remember, quadratic equations can often be simplified using techniques like completing the square or applying the quadratic formula. For instance, in \( 4 m^2 - 9 m - 9 \), look for two numbers that multiply to \( a*c \) (in this case, \(4 * -9\) = -36) while summing to \( b \) (-9). It's a puzzle waiting to be solved! Now, for polynomials like \( 10 x^3 + 15 x^2 - 10 x \), don't forget to factor out the greatest common factor first! Here, you can take out \( 5x \), leaving you with \( 2x^2 + 3x - 2 \). This step can make the rest of your factoring journey smoother and more manageable, just like finding the best route to a treasure in a pirate map!

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