Question
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\( \left. \begin{array} { l } { 3 = 10 \log \frac { I _ { 1 } } { I _ { 0 } } } \\ { \frac { I } { I _ { 0 } } = ? } \end{array} \right. \)

Ask by Coles Schneider. in Iran
Mar 08,2025

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Tutor-Verified Answer

Answer

\[ \frac{I}{I_0} = 10^{0.3} \]

Solution

1. Start with the given equation: \[ 3 = 10 \log \frac{I_1}{I_0} \] 2. Divide both sides by 10 to isolate the logarithm: \[ \frac{3}{10} = \log \frac{I_1}{I_0} \] 3. Rewrite the logarithmic equation in its exponential form: \[ \frac{I_1}{I_0} = 10^{\frac{3}{10}} \] 4. Recognize that the second line asks for \(\frac{I}{I_0}\). If we assume \(I = I_1\), then: \[ \frac{I}{I_0} = 10^{\frac{3}{10}} \] 5. Optionally, approximate the value: \[ 10^{\frac{3}{10}} \approx 10^{0.3} \approx 1.995 \, (\text{approximately } 2) \] Thus, the final answer is: \[ \frac{I}{I_0} = 10^{\frac{3}{10}} \]

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To find \( \frac{I}{I_0} \), we can start by manipulating the given equation \( 3 = 10 \log \frac{I_1}{I_0} \). First, divide both sides by 10: \[ \frac{3}{10} = \log \frac{I_1}{I_0} \] Now, to get rid of the logarithm, we convert from logarithmic form to exponential form: \[ \frac{I_1}{I_0} = 10^{\frac{3}{10}} \] Thus, the ratio \( \frac{I}{I_0} \) simplifies to: \[ \frac{I}{I_0} = 10^{0.3} \] So, \[ \frac{I}{I_0} \approx 2.0 \]

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