$$ HNO _ { 3 } + HCl \rightarrow NO + H _ { 2 } O + Cl _ { 2 } $$

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$$
2 \, HNO_3 + 6 \, HCl \rightarrow 2 \, NO + 4 \, H_2O + 3 \, Cl_2
$$

1. Sea la ecuación sin balancear:
   $$
   a \, HNO_3 + b \, HCl \rightarrow c \, NO + d \, H_2O + e \, Cl_2
   $$

2. Balanceamos átomo por átomo:

**Nitrógeno (N):**
   $$
   a = c
   $$

**Oxígeno (O):**
   $$
   3a = c + d \quad \Rightarrow \quad 3a = a + d \quad \Rightarrow \quad d = 2a
   $$

**Hidrógeno (H):**
   $$
   a + b = 2d \quad \Rightarrow \quad a + b = 2(2a) = 4a \quad \Rightarrow \quad b = 3a
   $$

**Cloro (Cl):**
   $$
   b = 2e \quad \Rightarrow \quad e = \frac{b}{2} = \frac{3a}{2}
   $$
   
   Para que $$e$$ sea entero, elegimos $$a = 2$$:
   $$
   a = 2,\quad c = 2,\quad d = 4,\quad b = 6,\quad e = \frac{3 \times 2}{2} = 3
   $$

3. La ecuación balanceada es:
   $$
   2 \, HNO_3 + 6 \, HCl \rightarrow 2 \, NO + 4 \, H_2O + 3 \, Cl_2
   $$
La ecuación balanceada es: $$ 2 \, HNO_3 + 6 \, HCl \rightarrow 2 \, NO + 4 \, H_2O + 3 \, Cl_2 $$

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