\( \left. \begin{array} { l } { \frac { x - y } { 2 } = \frac { y } { 3 } } \\ { x + y = 16 } \\ { \Rightarrow x \cdot y = ? } \end{array} \right. \)
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To solve the system of equations, we first manipulate the first equation: \[ \frac{x - y}{2} = \frac{y}{3} \] Multiplying both sides by 6 to eliminate the fractions gives: \[ 3(x - y) = 2y \implies 3x - 3y = 2y \implies 3x = 5y \implies y = \frac{3}{5}x \] Now, we substitute \(y\) into the second equation \(x + y = 16\): \[ x + \frac{3}{5}x = 16 \implies \frac{8}{5}x = 16 \implies x = 16 \cdot \frac{5}{8} = 10 \] Now we can find \(y\): \[ y = \frac{3}{5} \cdot 10 = 6 \] Finally, calculate \(x \cdot y\): \[ x \cdot y = 10 \cdot 6 = 60 \] So, the answer is \(60\).